\(M\le\frac{a}{\sqrt{2a}}+\frac{b}{\sqrt{2b}}+\frac{c}{\sqrt{2c}}=\frac{1}{\sqrt{2}}\left(\sqrt{a}+\sqrt{b}+\sqrt{c}\right)\)
\(M\le\frac{1}{\sqrt{2}}\sqrt{3\left(a+b+c\right)}\le\frac{3}{\sqrt{2}}\)
\(\Rightarrow M_{max}=\frac{3\sqrt{2}}{2}\) khi \(a=b=c=1\)