a: Trường hợp 1: x>=1
A=x-1-2x+5=-x+4
Trường hợp 2: x<1
A=1-x-2x+5=-3x+6
b: A=0 thì |x-1|=2x-5
\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{5}{2}\\\left(2x-5-x+1\right)\left(2x-5+x-1\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{5}{2}\\\left(x-4\right)\left(3x-6\right)=0\end{matrix}\right.\)
=>x=4