CT: FexOy
FexOy + yH2 \(\rightarrow\) xFe + yH2O
pt: 56x + 16y 56x
de: 7,2 5,6
Ta co:\(5,6\left(56x+16y\right)=7,2.56x\)
\(\Leftrightarrow313,6x+89,6y=403,2x\)
\(\Leftrightarrow89,6y=89,6x\Leftrightarrow\dfrac{x}{y}=\dfrac{89,6}{89,6}=\dfrac{1}{1}\)
\(\Rightarrow CT:FeO\)