ZnO +H2SO4---->ZnSO4 +H2O(1)
x---------x
CuO +H2SO4----->CuSO4 +H2O(2)
y--------y
n\(_{H2SO4}=0,6.0,5=0,3\left(mol\right)\)
Theo bài ra ta có pt
\(\left\{{}\begin{matrix}81x+60x=24,1\\x+y=0,3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x-0,1\\y=0,2\end{matrix}\right.\)
%m\(_{ZnO}=\frac{0,1.81}{24,1}.100\%=33,6\%\)
%m\(_{CuO}=100-33,6=66,4\%\)
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