Vì A trọng tâm tam giác BCN
\(\Rightarrow x_A=\frac{x_N+x_B+x_C}{3}\Leftrightarrow-2=\frac{x_N+1+2}{3}\)
\(\Rightarrow x_N=-9\)
\(y_A=\frac{y_N+y_B+y_C}{3}\Leftrightarrow4=\frac{y_N-3+1}{3}\)
\(\Rightarrow y_N=14\)
\(\Rightarrow N\left(-9;14\right)\)