a) \(Mg+2HCl-->MgCl2+H2\)
x-----------------------------------------x(mol)
\(2Al+6HCl-->2AlCl3+3H2\)
y--------------------------------------1,5y(mol)
\(Zn+2HCl-->ZnCl2+H2\)
z---------------------------------------z(mol)
\(n_{H2}=\frac{16,352}{22,4}=0,73\left(mol\right)\)
Theo bài ra ta có hpt
\(\left\{{}\begin{matrix}24x=17y\\24x+27y+65z=19,46\\x+1,5y+z=0,73\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,27\\y=0,24\\z=0,1\end{matrix}\right.\)
\(\%m_{Mg}=\frac{0,27.24}{19,46}.100\%=33,3\%\)
\(\%m_{Al}=\frac{0,24.27}{19,46}.100\%=33,3\%\)
\(\%m_{Zn}=100-33,3-33,3=33,4\%\)
b) \(n_{HCl}=2n_{H2}=1,46\left(mol\right)\)
\(V_{HCl}=\frac{1,46}{2}=0,73\left(l\right)\)
Do dùng dư 10%
\(\Rightarrow V_{HCl}=0,73+0,73.10\%=0,803\left(l\right)\)
