2Al+3H2SO4->Al2(SO4)3+3H2
0,4---0,6
n Al=0,4 mol
=>VH2SO4=\(\dfrac{0,6}{0,2}=3l\)
\(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\\
PTHH:2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\uparrow\)
\(LTL:\dfrac{0,4}{2}>\dfrac{0,2}{3}\)
thấy \(n_{H_2SO_4\left(th\text{ê}m\right)}=n_{Al\left(b\text{đ}\right)}-n_{H_2SO_4\left(b\text{đ}\right)}\\
\Leftrightarrow n_{H_2SO_4\left(th\text{ê}m\right)}=0,4-0,2=0,2\left(mol\right)\)
\(=>V_{H_2SO_4}=0,2.22,4=4,48\left(l\right)\)
TK
2Al+3H2SO4->Al2(SO4)3+3H2
0,4---0,6
n Al=0,4 mol
=>VH2SO4=