Phân thức đại số
Các câu hỏi tương tự
27 tháng 8 2021 lúc 20:08
Tìm x biết:
a, \(ax-x+1=a^2\) \(\left(a\ne1\right)\)
b, \(a^2x+x=2a^2-3\)
c, \(a^2x+3ax+9=a^2\) \(\left(a\ne0;a\ne-3\right)\)
Tìm các số A, B, C để có:
a) \(\dfrac{x^2-x+2}{\left(x-1\right)^3}=\dfrac{A}{\left(x-1\right)^3}+\dfrac{B}{\left(x-1\right)^2}+\dfrac{C}{x-1}\)
b) \(\dfrac{x^2+2x-1}{\left(x-1\right)\left(x^2+1\right)}=\dfrac{A}{x-1}+\dfrac{Bx+C}{x^2+1}\)
Tính
a)left(dfrac{left(x-1right)^2}{left(3x+x-1right)^2}-dfrac{1-2x^2+4x}{x^3-1}+dfrac{1}{x-1}right):dfrac{x^2+x}{x^2+1}
b)left(dfrac{3left(x+2right)}{2left(x^3+x^2+x+1right)}+dfrac{2x^2-x+10}{2left(x^3+x^2+x+1right)}right):left(dfrac{5}{x^2+1}+dfrac{3}{2left(x+1right)}-dfrac{3}{2left(x-1right)}right).dfrac{2}{x-1}
c)left(dfrac{x^2}{x^2-5x+6}+dfrac{x^2}{x^2-3x+2}right):dfrac{left(x-1right)left(x-3right)}{x^4+x^2+1}
Đọc tiếp
Tính
a)\(\left(\dfrac{\left(x-1\right)^2}{\left(3x+x-1\right)^2}-\dfrac{1-2x^2+4x}{x^3-1}+\dfrac{1}{x-1}\right):\dfrac{x^2+x}{x^2+1}\)
b)\(\left(\dfrac{3\left(x+2\right)}{2\left(x^3+x^2+x+1\right)}+\dfrac{2x^2-x+10}{2\left(x^3+x^2+x+1\right)}\right):\left(\dfrac{5}{x^2+1}+\dfrac{3}{2\left(x+1\right)}-\dfrac{3}{2\left(x-1\right)}\right).\dfrac{2}{x-1}\)
c)\(\left(\dfrac{x^2}{x^2-5x+6}+\dfrac{x^2}{x^2-3x+2}\right):\dfrac{\left(x-1\right)\left(x-3\right)}{x^4+x^2+1}\)
B1: Tính:
Bdfrac{4.left(x+3right)^2}{left(3x+5right)^2-4x^2}-dfrac{x^2-25}{9x^2-left(2x+5right)^2}-dfrac{left(2x+3right)^2-x^2}{left(4x+15right)^2-x^2}
B2: Xác định a, b, c:
a, dfrac{10x-4}{x^3-4x}dfrac{a}{x}+dfrac{b}{1-2}+dfrac{c}{n+2} với mọi x khác 0, x khác pm2
b, dfrac{1}{x^3-1}dfrac{a}{x-1}+dfrac{bx+c}{x^2+x+1}
Help me!!!
Đọc tiếp
B1: Tính:
\(B=\dfrac{4.\left(x+3\right)^2}{\left(3x+5\right)^2-4x^2}-\dfrac{x^2-25}{9x^2-\left(2x+5\right)^2}-\dfrac{\left(2x+3\right)^2-x^2}{\left(4x+15\right)^2-x^2}\)
B2: Xác định a, b, c:
a, \(\dfrac{10x-4}{x^3-4x}=\dfrac{a}{x}+\dfrac{b}{1-2}+\dfrac{c}{n+2}\) với mọi x khác 0, x khác \(\pm2\)
b, \(\dfrac{1}{x^3-1}=\dfrac{a}{x-1}+\dfrac{bx+c}{x^2+x+1}\)
Help me!!!
Rút gọn phân thức sau:
A = \(\dfrac{\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)+1}{x^2+5x+5}\)
B = \(\dfrac{\left|x-1\right|+\left|x\right|+x}{3x^2-4x+1}\) với x < 0
giải phương trình
a.\(\left(2x-3\right)^2=\left(2x-3\right)\left(x+1\right)\)
b.\(x\left(2x-9\right)=3x\left(x-5\right)\)
c.\(3x-15=2x\left(x-5\right)\)
d.\(\dfrac{5-x}{2}=\dfrac{3x-4}{6}\)
e.\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=2x+\dfrac{5}{3}\)
A=\(\dfrac{4x^2+\left(2x+3\right)\left(x+1\right)-9}{9x^2-4}\)
a) Rút gọn A
b) Tìm các số nguyên x để A đạt giá trị nguyên
Làm tính nhanh (làm kĩ giúp ạ)
\(\dfrac{1}{x\left(x+1\right)}+\dfrac{1}{\left(x+1\right)\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+3\right)}+\dfrac{1}{\left(x+3\right)\left(x+4\right)}+\dfrac{1}{\left(x+4\right)\left(x+5\right)}+\dfrac{1}{\left(x+5\right)\left(x+6\right)}\)
Tìm x ϵ Z để : a) A = \(\dfrac{x^2-1}{x+2}\) có giá trị nguyên.
b) B = \(\dfrac{\left(x+1\right)^2+\left(x-1\right)^2}{2x^2-1}\) có giá trị nguyên.
c) C = \(\dfrac{2x-3}{3x-2}\) có giá trị nguyên.
d) D = \(\dfrac{x-1}{x^2+1}\) có giá trị nguyên.