a \(\frac{19}{13}>\frac{87}{65}\)
b, \(\frac{5}{17}< \frac{11}{34}\)
c, \(-0,22\left(23\right)< -0,2223\)
a, ta có \(\frac{19}{13}=\frac{19.5}{13.5}=\frac{95}{65}\)
và \(\frac{87}{65}\)
vì 95 > 87 => \(\frac{95}{65}>\frac{87}{65}\)nên \(\frac{19}{13}>\frac{87}{65}\)
b, làm tương tự \(\left(\frac{5}{17}=\frac{5.2}{17.2}=\frac{10}{34}\right)\)
c, -0,22(23) = \(-\frac{7}{30}=-\frac{7000}{30000}\);-0,2223 = \(-\frac{2223}{10000}=-\frac{6669}{30000}\)
mà \(-\frac{7000}{30000}< -\frac{6669}{30000}\Rightarrow-0,22\left(23\right)< -0,2223\)