\(a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)\)
\(=\left(a+b\right)\left(a^2+b^2-ab\right)\)
\(=\left(a+b\right)\left[\left(a+b\right)^2-ab\right]\)\(\left(1\right)\)
Thay \(a+b=-5;ab=3\) vào \(\left(1\right):\)
\(\left(-5\right).\left[\left(-5\right)^2-3\right]=-110\)
tham khảo
https://hamchoi.vn/cau-hoi/10743/gia-tri-cua-bieu-thuc-q-a3-b3-biet-a-b-5-va-ab-3