3)\(\sqrt{3m-2x}-2x-2=0\)
\(\Leftrightarrow3m-2x=4x^2+8x+4\) ( đk \(x\ge-1\) )
\(\Leftrightarrow4x^2+10x-3m+4=0\)
\(\Delta=10^2-4.4.\left(-3m+4\right)=100+48m-64=48m+36\)
để pt có nghiệm khi \(\Delta=0\Leftrightarrow48m+36=0\Leftrightarrow m=-\dfrac{3}{4}\)
vậy ..................