\(2a,A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(=-a-b+c-a+b+c\)
\(=\left(-a-a\right)+\left(-b+b\right)+\left(c+c\right)\)
\(=-2a+0+2c\)
\(=2c-2a\)
\(b,\) Thay \(a=2018;c=-2\) vào biểu thức trên ta được:
\(2.\left(-2\right)-2.2018=-4-4036=-4040\)
Vậy ...........
\(1,xy+y+x=4\)
\(\Leftrightarrow xy+y+x+1=5\)
\(\Leftrightarrow\left(x+1\right)\left(y+1\right)=5\)
\(\Rightarrow\left(x+1\right),\left(y+1\right)\inƯ\left(5\right)\)
\(\Rightarrow\left(x+1;y+1\right)\in\left\{\left(5;1\right);\left(1;5\right);\left(-5;-1\right);\left(-1;-5\right)\right\}\)
\(\Rightarrow\left(x;y\right)\in\left\{\left(4;0\right);\left(0;4\right);\left(-6;-2\right);\left(-2;-6\right)\right\}\)
\(2a,A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(=-a-b+c+a+b+c\)
\(=2c\)
\(b,Thay:a=2018;b=-1;c=-2\) vào biểu thức trên ta được:
\(A=2.\left(-2\right)=-4\)
Vậy............................