Ta có:
\(A=\dfrac{\sqrt{4-4\sqrt{3}+3}}{\sqrt{2-\sqrt{3}}}\cdot\sqrt{2+\sqrt{3}}\\ =\dfrac{\sqrt{\left(2-\sqrt{3}\right)^2}}{\sqrt{2-\sqrt{3}}}\cdot\sqrt{2+\sqrt{3}}\\ =\dfrac{2-\sqrt{3}}{\sqrt{2-\sqrt{3}}}\cdot\sqrt{2+\sqrt{3}}\\ =\sqrt{2-\sqrt{3}}\cdot\sqrt{2+\sqrt{3}}\\ =2^2-\left(\sqrt{3}\right)^2\\ =4-3\\ =1\)
Chúc bạn học tốt .