Để A nhận giá trị nguyên thì \(5⋮n-3\)
\(\Rightarrow n-3\inƯ\left(5\right)\)
mà \(Ư\left(5\right)=\left\{\pm1;\pm5\right\}\)
\(\Rightarrow n-3\in\left\{\pm1;\pm5\right\}\)
_ Nếu \(n-3=1\Rightarrow n=4\)
_ Nếu \(n-3=-1\Rightarrow n=2\)
_ Nếu \(n-3=5\Rightarrow n=8\)
_ Nếu \(n-3=-5\Rightarrow n=-2\)
Vậy \(n\in\left\{4;2;8;-2\right\}\)