\(\dfrac{1}{\sqrt{x}+3}-\dfrac{\sqrt{x}-3}{x-9}\)
\(=\dfrac{1}{\sqrt{x}+3}-\dfrac{\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=\dfrac{1}{\sqrt{x}+3}-\dfrac{1}{\sqrt{x}+3}=0\)
\(B=\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{x+9\sqrt{x}}{9-x};\left(x\ge0;x\ne9;x\ne16\right)\)
\(B=\dfrac{3}{\sqrt{x}-3}+\dfrac{2}{\sqrt{x}+3}+\dfrac{x-5\sqrt{x}-3}{x-9}\)
\(B=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}-\dfrac{x+\sqrt{x}}{x-1};\left(x>0;x\ne1\right)\)
A=(\(\dfrac{\sqrt{x}}{\sqrt{x}+3}-\dfrac{x+9}{x-9}\)):(\(\dfrac{3\sqrt{x+1}}{x-3\sqrt{x}}-\dfrac{1}{\sqrt{x}}\)) (với x>0,x khác 9)
a,rút gọn biểu thức A
b,tìm x sao cho A>-1
A= \(\left[\left(\dfrac{2\sqrt{x}}{\sqrt{x}+3}\right)+\dfrac{\sqrt{x}}{\sqrt{x}+3}+3\left(\dfrac{\sqrt{x}}{x-9}\right)\right]:\left(\dfrac{2\sqrt{x}-2}{\sqrt{x}-3}-\dfrac{1}{1}\right)\)với x>= 0 , x #9
cho biểu thức B=(1/(sqrt(x) + 3) + (2sqrt(x))/(x - 9) ) 2 sqrt x +6 sqrt x -1 với x >= 0 x ne1;x ne9 a) rút gọn B
cho biểu thức
P=\(\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}-\dfrac{x+9}{9-x}\right):\left(\dfrac{3\sqrt{x}+1}{x-3\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right)\)với x>0,x\(\ne\)9
a, rút gon P
b,tìm x sao cho P<-1
Rút gọn biểu thức
P=\(\left(\dfrac{1}{\sqrt{x}-3}-\dfrac{1}{\sqrt{x}+3}\right):\dfrac{1}{\sqrt{x}-3}\)với x\(\ge\)0 ;x\(\ne\)9
1. rút gọn bt
Q= \(\left(\dfrac{3+\sqrt{x}}{3-\sqrt{x}}-\dfrac{3-\sqrt{x}}{3+\sqrt{x}}-\dfrac{36}{x-9}\right):\dfrac{\sqrt{x}-5}{3\sqrt{x}-x}\)
b, tìm để Q<0
cho hai biểu thức A=\(\frac{x+2\sqrt{x}+5}{\sqrt{x-3}}\)và B=\(\frac{2\sqrt{x}-9}{x-5\sqrt{x}+6}-\frac{\sqrt{x}+3}{\sqrt{x}-2}-\frac{2\sqrt{x}+1}{3-\sqrt{x}}\)với x≥0,x≠4 và x≠9
a) rút gọn B
b)đặt P=\(\frac{A}{B}\)tìm giá trị nhỏ nhất
\(A=\dfrac{\sqrt{x}+2}{\sqrt{x}-2}-\dfrac{3}{\sqrt{x}+2}+\dfrac{12}{x-4}\)
\(B=\dfrac{\sqrt{x}}{\sqrt{x}-3}-\dfrac{\sqrt{x}-21}{9-x}\dfrac{1}{\sqrt{x}+3}\)
\(C=\dfrac{\sqrt{x}}{\sqrt{x}+3}+\dfrac{2\sqrt{x}}{\sqrt{x}-3}-\dfrac{3x+9}{x-9}\)
\(D=\dfrac{1}{\sqrt{x}+3}-\dfrac{\sqrt{x}}{3-\sqrt{x}}+\dfrac{2\sqrt{x}+12}{x-9}\)
\(N=\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}-\dfrac{6}{x-1}\)
\(M=\dfrac{3}{\sqrt{x}-3}+\dfrac{2}{\sqrt{x}+3}+\dfrac{x-5\sqrt{x}-3}{x-9}\)
