\(a,\left|x+\dfrac{4}{5}\right|-\dfrac{1}{7}=0\\ \Rightarrow\left|x+\dfrac{4}{5}\right|=\dfrac{1}{7}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{5}=\dfrac{1}{7},\forall x+\dfrac{4}{5}\ge0\\x+\dfrac{4}{5}=-\dfrac{1}{7},\forall x+\dfrac{4}{5}< 0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{23}{35},\forall x\ge-\dfrac{4}{5}\left(N\right)\\x=-\dfrac{33}{35},\forall x< -\dfrac{4}{5}\left(N\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{23}{35}\\x=-\dfrac{33}{35}\end{matrix}\right.\)
\(b,\left|x-2\right|=x-2\\ \Rightarrow\left[{}\begin{matrix}x-2=x-2,\forall x-2\ge0\\x-2=2-x,\forall x-2< 0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0,\forall x\ge2\left(L\right)\\x=2,\forall x< 2\left(L\right)\end{matrix}\right.\\ \Rightarrow x\in\varnothing\)
