a) S=1+52+54+.....+5200
=>52S=25S=52+54+56+.....+5202
=>25S-S=(52+54+56+....+5202)-(1+52+54+......+5200)
=>24S=5202-1
=>S=\(\frac{5^{202}-1}{24}\)
b) Ta có: \(4^{30}=2^{30}.2^{30}=\left(2^3\right)^{10}.\left(2^2\right)^{15}=8^{10}.4^{15}>8^{10}.3^{15}>8^{10}.3^{11}=8^{10}.3^{10}.3=3.24^{10}\)
Vậy \(2^{30}+3^{30}+4^{30}>3.24^{10}\)
b) Link nè
https://hoc24.vn/hoi-dap/question/393164.html