a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))
=((-2,5.0,4).0,38) - ((-8.0,125).3,15)
= ((-1).0,38) - ((-1).3,15)
= -0,38 - (-3,15)
= 2.77
b) ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)
= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)
= (-6) : 3
= -2
a)\(\left(-2,5.0,38.0,4\right)-\left[0,125.3,15\left(-8\right)\right]\)
\(=-20.0,125.0,38.0,4-0,125.3,15\left(-20\right).0,4\)
\(=-20.0,125.0,4\left(0,38-3,15\right)\)
\(=-1\left(-2,77\right)=2,77\)
b)\(\left[-20,83.0,2+\left(-9,17.0,2\right)\right]:\left[2,47.0,5-\left(-3,53\right).0,5\right]\)
\(=\left[0,2\left(-20,83-9,17\right)\right]:\left[0,5\left(2,47+3,53\right)\right]\)
\(=\dfrac{0,2\left(-30\right)}{0,5.6}=\dfrac{-6}{3}=-2\)