a: Sửa đề: \(A=\left(\dfrac{\sqrt{x}+1}{x-1}-\dfrac{\sqrt{x}-1}{\left(\sqrt{x}+1\right)^2}\right)\cdot\dfrac{\left(1-x\right)^2}{2}\)
\(=\dfrac{x+2\sqrt{x}+1-x+2\sqrt{x}-1}{\left(\sqrt{x}+1\right)^2\cdot\left(\sqrt{x}-1\right)}\cdot\dfrac{\left(x-1\right)^2}{2}\)
\(=\dfrac{4\sqrt{x}\left(\sqrt{x}-1\right)}{2}=2\sqrt{x}\left(\sqrt{x}-1\right)\)
b: Để A>0 thì căn x-1>0
=>x>1