Question

A=\(\dfrac{x+2}{x+3}\)-\(\dfrac{5}{\left(x-2\right)\left(x+3\right)}\)

Rút gọn A

Answer 1

A=-

A=\(\dfrac{x+2}{x+3}+\left(\dfrac{-5}{\left(x-2\right)\left(x+3\right)}\right)\)

A=\(\dfrac{\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x+3\right)}+\dfrac{-5}{\left(x-2\right)\left(x+3\right)}\)

A=\(\dfrac{x^2-9}{\left(x-2\left(x+3\right)\right)}\)

A=\(\dfrac{\left(x-3\right)\left(x+3\right)}{\left(x-2\right)\left(x+3\right)}\)

A=\(\dfrac{x-3}{x-2}\)