a: \(A=\dfrac{4\left(x+2\right)-5\left(3x-7\right)}{20}=\dfrac{4x+8-15x+35}{20}=\dfrac{-11x+43}{20}\)
Để A>0 thì -11x+43>0
=>-11x>-43
hay x<43/11
b: Để B>0 thì -8x+7>0
=>-8x>-7
hay x<7/8
c: \(C=\dfrac{\left(x-2\right)^2}{\left(x-2\right)\left(x^2-4\right)}=\dfrac{1}{x+2}\)
Để C>0 thì x+2>0
hay x>-2