Question

\(A=\dfrac{3n+2}{n-1}\)

Answer 1

\(A=\dfrac{3n+2}{n-1}=\dfrac{3+5}{n-1}\)

Để \(3n+2⋮n-1\) thì \(n-1\inƯ\left(5\right)\)

Do đó:

\(n-1=1\Rightarrow n=2\)

\(n-1=-1\Rightarrow n=0\)

\(n-1=5\Rightarrow n=6\)

\(n-1=-5\Rightarrow n=-4\)

Vậy \(n=\left\{-4;0;2;6\right\}\) thì \(3n+2⋮n-1\)

Answer 2

Suy ra : 1/3A=3n+2/3n-3=3n+2/3n+2-5

1/3A=1-5/3n+2