\(\frac{\left(a+b\right)^2-c^2}{a+b+c}=\frac{\left(a+b+c\right)\left(a+b-c\right)}{a+b+c}=...\)
And... u know dat? =))
Chúc bạn học tốt nha
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\(\frac{\left(a+b\right)^2-c^2}{a+b+c}=\frac{\left(a+b+c\right)\left(a+b-c\right)}{a+b+c}=\frac{a+b-c}{a+b+c}\)
\(\left(a+b\right)^2-c^2=\left(a+b+c\right)\left(a+b-c\right)\Rightarrow\frac{\left(a+b\right)^2-c^2}{a+b-c}=a+b-c\)

