\(A=1-\left|3x-1\right|+\left(3x-1\right)^2\)
\(=\left(\left|3x-1\right|\right)^2-2\cdot\left|3x-1\right|\cdot\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{3}{4}\)
\(=\left(\left|3x-1\right|-\dfrac{1}{2}\right)^2+\dfrac{3}{4}>=\dfrac{3}{4}\)
Dấu '=' xảy ra khi 3x-1=1/2 hoặc 3x-1=-1/2
=>3x=3/2 hoặc 3x=1/2
=>x=1/6 hoặc x=1/2