a: \(\Leftrightarrow\left(2x-1\right)\left(2x-1-1\right)\left(2x-1+1\right)=0\)
=>2x(2x-1)(2x-2)=0
hay \(x\in\left\{0;\dfrac{1}{2};1\right\}\)
c: =>1/3x-1=1/4 hoặc 1/3x-1=-1/4
=>1/3x=5/4 hoặc 1/3x=3/4
=>x=15/4 hoặc x=9/4
1. Tìm x :
a) ( x - 3 ) . ( 2x + 5 ) > 0
b)( 1 - 4x ) . ( x - 2 ) < 0
c) \(\dfrac{-3}{x+2}< 0\)
b)\(\dfrac{x-3}{2x-1}>0\)
e) \(\dfrac{4x+1}{x+1}\)
Cho 2 đa thức : \(f(x)=4x^2+3x+1 \) và \(g(x)=3x^2-2x+1\)
a, Tính \(h(x)=f(x)-g(x)\)
b, Tìm nghiệm của đa thức \(h(x)\)
c, Tính giá trị của đa thức \(h(x)\) với \((x^2-9)^{2011}=(\dfrac{3}{4}-81).(\dfrac{3^2}{5}-81)^2.(\dfrac{3^3}{6}-81)^3...(\dfrac{3^{2010}}{2013}-81)^{2010}\)
Tìm x
a) |x|=\(\dfrac{1}{2}\)
b)|2x+\(\dfrac{1}{2}\)|=\(\dfrac{3}{4}\)
c)|2x+\(\dfrac{3}{4}\)|-\(\dfrac{-1}{2}\)= \(\dfrac{5}{2}\)
d)|2x+1|=x+1
e)|2x+1|+|4x+2|+|6x+5|=5
f)|x|≤ 3 (x∈Z)
h) |x+\(\dfrac{1}{2}\)| + | x + \(\dfrac{1}{3}\)| + | x+ \(\dfrac{1}{4}\)| = x
Các bạn ơi !!!! giúp mình nha mình cần gấp lắm!!! ai đúng mình sẽ tick cho nhé iu các bạn <3
Tìm x :
a) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}+\dfrac{1}{2x-3}-\dfrac{3}{2}\)
b) \(7.\left(x.1\right)+2x.\left(1-x\right)=0\)
c) \(\dfrac{x+1}{2018}+\dfrac{x+2}{2017}+\dfrac{x+3}{2016}=\dfrac{x+10}{2009}+\dfrac{x+11}{2008}+\dfrac{x+12}{2007}\)
Có 3 ý thui các bạn hãy giúp mk!!!!!!
2. Tìm x:
A, \(\dfrac{5}{2}\)*x-\(\dfrac{1}{3}\)*X+2=\(\dfrac{3}{2}\) B, (2X-1)^2=\(\dfrac{1}{4}\)
C, ( X^2-16)*(4-5*X)=0 D, \(\dfrac{2\cdot X-1}{3}\)=\(\dfrac{X+2}{3}\)
Tìm x biết:
a) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
b) \(\left(x^4\right)^2=\dfrac{x^{12}}{x^5}\left(x\ne0\right)\)
c) \(\left(2x+3\right)^2=\dfrac{9}{121}\)
d) \(\left(2x-1\right)^3=\dfrac{-8}{27}\)
Tìm x :
a) \(3^{x+1}+2x.3^x-18x-27=0\)
b) \(\dfrac{1}{2}\left|2x+5\right|-\dfrac{5}{4}\left|4x+10\right|+\dfrac{7}{3}\left|-20-8x\right|=\dfrac{1}{6}\)
Bai 1: Tim x
a) \(|\text{x-1|+|2x+4|=3}\)
b) \(|x+\dfrac{1}{3}|=|3x-\dfrac{5}{6}|\)
c) 4x.\(\left(x+\dfrac{1}{2}\right)=0\)
d) 3x.(x+2)-5(x+2)=0
tìm x để các p số sau là số nguyên:
A=\(\dfrac{x+1}{x-1}\)
B=\(\dfrac{2x-1}{x+5}\)
C=\(\dfrac{10x-9}{2x-3}\)
D=\(\dfrac{x^2-4x-4}{x-7}\)
E=\(\dfrac{3x-4}{2x-3}\)
