\(a,\dfrac{2}{5}+3=\dfrac{2}{5}+\dfrac{15}{5}=\dfrac{17}{5}\\ b,4+\dfrac{2}{3}=\dfrac{12}{3}+\dfrac{2}{3}=\dfrac{14}{3}\)
a.\(\dfrac{2}{5}+3=\dfrac{2}{5}+\dfrac{15}{5}=\dfrac{17}{5}\)
b.\(4+\dfrac{2}{3}=\dfrac{12}{3}+\dfrac{2}{3}=\dfrac{14}{3}\)
\(a.\dfrac{2}{5}+3=\dfrac{2+15}{5}=\dfrac{17}{5}\\ b.4+\dfrac{2}{3}=\dfrac{12+2}{3}=\dfrac{14}{3}\)