\(9x^2-6x=8\)
\(9x^2-6x+1=9\)
\(\left(3x-1\right)^2=\left(\pm3\right)^2\)
\(\left[\begin{array}{nghiempt}3x-1=3\\3x-1=-3\end{array}\right.\)
\(\left[\begin{array}{nghiempt}3x=3+1\\3x=-3+1\end{array}\right.\)
\(\left[\begin{array}{nghiempt}3x=4\\3x=-2\end{array}\right.\)
\(\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{2}{3}\end{array}\right.\)
9x2-6x=8
<=>9x2-6x+1=9
<=>(3x-1)2=9
<=> 3x-1 = \(\pm3\)
<=> 3x-1=-3 hoặc 3x-1=3
=> \(x=\frac{-2}{3}\) hoặc \(x=\frac{4}{3}\)