Question

√8+√32+√72

Answer 1

\(\sqrt{8}+\sqrt{32}+\sqrt{72}\)

\(=2\sqrt{2}+4\sqrt{2}+6\sqrt{2}\)

\(=12\sqrt{2}\)

Answer 2

a) \(\sqrt{8}+\sqrt{32}+\sqrt{72}=2\sqrt{2}+4\sqrt{2}+6\sqrt{2}=12\sqrt{2}\)

c) \(2\sqrt{5}+3\sqrt{75}=2\sqrt{5}+15\sqrt{3}\)

d) \(3\sqrt{112}-7\sqrt{126}+4\sqrt{54}-2\sqrt{252}=12\sqrt{7}-21\sqrt{14}+12\sqrt{6}-12\sqrt{7}=12\sqrt{6}-21\sqrt{14}\)

e) \(2\sqrt{18}+3\sqrt{80}-5\sqrt{147}+5\sqrt{245}=6\sqrt{2}+12\sqrt{5}-35\sqrt{3}+35\sqrt{5}=6\sqrt{2}+47\sqrt{5}-35\sqrt{3}\)