`6x^2 + 2x`
`2x.(3x+1)`
Đặt bằng `0`
`2x.(3x+1)=0`
`=>` \(\left[{}\begin{matrix}2x=0\\3x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0:2=0\\3x=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{3}\end{matrix}\right.\)
Vậy `x = {0; (-1)/3}`
\(GCF=2x\)
\(=\)\(2x\left(\dfrac{6x^2}{2x}+\dfrac{2x}{2x}\right)\)
\(=\)\(2x\left(3x+1\right)\)