5(x-4)=-7x+16
⇒5x-20=-7x+16
⇒5x+7x=16+20
⇒12x=36
⇒x=3
Ta có: 5(x-4)=-7x+16
\(\Leftrightarrow5x-20+7x-16=0\)
\(\Leftrightarrow12x-36=0\)
\(\Leftrightarrow12x=36\)
hay x=3
Vậy: x=3
5.(x-4)=-7x+16
5x+5.4=-7x+16
5x+20=-7x+16
5x-(-7x)=16-20
5x+7x=-4
12x=-4
x=-4:12
x=\(\frac{-1}{3}\)
\(5\cdot\left(x-4\right)=-7\cdot x+16\)
\(5\cdot x-5\cdot4=-7\cdot x+16\)
\(5\cdot x+7\cdot x=16-20\)
\(12\cdot x=-4\)
\(x=-\frac{4}{12}=-\frac{1}{3}\)
Vậy \(x=-\frac{1}{3}\)
