\(\dfrac{5}{9}+\dfrac{1}{3}x=\dfrac{2}{3}\\ \Rightarrow\dfrac{1}{3}x=\dfrac{2}{3}-\dfrac{5}{9}\\ \Rightarrow\dfrac{1}{3}x=\dfrac{2\times3-5}{9}\\ \Rightarrow\dfrac{1}{3}x=\dfrac{1}{9}\\ \Rightarrow x=\dfrac{1}{9}:\dfrac{1}{3}\\ \Rightarrow x=\dfrac{1}{3}\)
Vậy \(x=\dfrac{1}{3}\)
\(\dfrac{5}{9}+\dfrac{1}{3}x=\dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{1}{3}x=\dfrac{2}{3}-\dfrac{5}{9}\)
\(\Leftrightarrow\dfrac{1}{3}x=\dfrac{1}{9}\)
\(\Leftrightarrow x=\dfrac{1}{3}\)