Question

4.(x-3)²-(2x-1).(2x+1)=10

Answer 1

Answer 2

(x-3)² - (2x-1)(2x+1) = 10

<=> x² - 6x + 9 - 4x² + 1 = 10

<=> -3x² - 6x = 0

<=> x² + 2x = 0

<=> x(x + 2) = 0

<=> \(\left\{{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)

vậy ....

Answer 3

\(4(x-3)\)\(^2\) \(-(2x-1)(2x+1)=10\)

\(=> 4(x\)\(^2\) \(-6x+9)-4x\)\(^2\)\(-1=10\)

\(=>\)\(4x\)\(^2\)\(-24x+36-4x\)\(^2\) \(+1=10\)

            \(=>-24x+27=10\)

            \(=>-24x=-27\)

             \(=>x=\)\(\dfrac{-27}{-24}\)\(=\) \(\dfrac{9}{8}\)

                             \(Vậy \)\(X=\)\(\dfrac{9}{8}\)

         Nhớ vote cho mik hen