\(\Leftrightarrow\frac{4}{5}sinx-\frac{3}{5}cosx=1\)
Đặt \(cosa=\frac{4}{5}\) với \(a\in\left(0;\pi\right)\)
\(\Rightarrow sinx.cosa-cosx.sina=1\)
\(\Leftrightarrow sin\left(x-a\right)=1\)
\(\Leftrightarrow x-a=\frac{\pi}{2}+k2\pi\)
\(\Leftrightarrow x=a+\frac{\pi}{2}+k2\pi\)