Question

(4n+3)⋮(2n+1)

Answer 1

Ta có:

\(4n+3⋮2n+1\)

\(\Rightarrow\left(4n+2\right)+1⋮2n+1\)

\(\Rightarrow2\left(2n+1\right)+1⋮2n+1\)

\(\Rightarrow1⋮2n+1\)

\(\Rightarrow2n+1\in U\left(1\right)=\left\{-1;1\right\}\)

\(\Rightarrow\left\{{}\begin{matrix}2n+1=-1\Rightarrow n=-1\\2n+1=1\Rightarrow n=0\end{matrix}\right.\)

Vậy \(n\in\left\{-1;0\right\}\)

Answer 2

2(2n+1)+1 chia hết cho 2n+1

\(\Rightarrow\)1 chia hết cho 2n+1

\(\Rightarrow\)2n+1\(\in\)Ư(1)=\(\left\{\pm1\right\}\)

2n+1=1\(\Rightarrow\)n=0

2n+1=-1\(\Rightarrow\)n=-1

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