Question

4/3 nhân x - 3/4 + 1/2 - x = -1/12

Answer 1

\(\dfrac{4}{3}\times x-\dfrac{3}{4}+\dfrac{1}{2}-x=-\dfrac{1}{12}\\ =>x\left(\dfrac{4}{3}-1\right)+\left(-\dfrac{3}{4}+\dfrac{1}{2}\right)=-\dfrac{1}{12}\\ =>\dfrac{1}{3}x+\left(\dfrac{-3}{4}+\dfrac{2}{4}\right)=-\dfrac{1}{12}\\ =>\dfrac{1}{3}x-\dfrac{1}{4}=-\dfrac{1}{12}\\ =>\dfrac{1}{3}x=\left(-\dfrac{1}{12}\right)+\dfrac{1}{4}\\ =>\dfrac{1}{3}x=\dfrac{-1}{12}+\dfrac{3}{12}\\ =>\dfrac{1}{3}x=\dfrac{1}{6}\\ =>x=\dfrac{1}{6}:\dfrac{1}{3}\\ =>x=\dfrac{1}{2}\)

Answer 2

\(\dfrac{4}{3}.x-\dfrac{3}{4}+\dfrac{1}{2}-x=-\dfrac{1}{12}\)

\(\Rightarrow\dfrac{1}{3}x=-\dfrac{1}{12}+\dfrac{3}{4}-\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{3}x=\dfrac{1}{6}\)

\(\Rightarrow x=\dfrac{1}{6}:\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{1}{6}.3\)

\(\Rightarrow x=\dfrac{1}{2}\)