3.|x| + 9 = 24
=> 3.|x| = 24 -9
=> 3.|x| = 15
=>|x| = 15 : 3
=> |x| = 5
=> x\(\in\) { -5 ; 5}
\(3\left|x\right|+9=24\\ \Rightarrow3\left|x\right|=24-9\\ \Rightarrow3\left|x\right|=15\\ \Rightarrow\left|x\right|=\dfrac{15}{3}\\ \Rightarrow\left|x\right|=5\\ \Rightarrow x=\pm5\)
Vậy \(x\in\left\{5;-5\right\}\)