3x+3x+1+3x+2=177
9x+3=117
9x=117-3
9x=114
x=114/9
\(3x+3x+1+3x+2=117\)
\(\Leftrightarrow\left(3x+3x+3x\right)+\left(1+2\right)=117\)
\(\Leftrightarrow9x+3=117\)\(\Rightarrow9x=114\Rightarrow x=\frac{114}{9}\)
\(\text{Vậy x=}\frac{114}{9}\)
3x+3x+1+3x+2=117
=>3x.3 +(1+2) = 117
=>9x +3 = 117
=> 9x = 114
=> x = \(\frac{38}{3}\)
\(3^x\)+ 3 · \(3^x\)+ 3² · \(3^x\) = 117
ký hiệu là \(3^x\)= t
t + 3t + 9t = 117
13T = 117
t = 117/13
t = 9
\(3^x\) = 9
\(3^x\) = 3²
x = 2
