\(3^{x+1}+3^{x+3}=810\)
\(\Rightarrow3^x.3+3^x.27=810\)
\(\Rightarrow3^x\left(3+27\right)=810\)
\(\Rightarrow3^x.30=810\)
\(\Rightarrow3^x=27\Rightarrow x=3\)
`[101]`
`3^x . 3 + 3^x . 27 = 810`
`3^x . 30 = 810`
`3^x = 27`
`-> x = 3`.
\(3^{x+1}+3^{x+3}=810\)
\(\Rightarrow3^x.3+3^x.27=810\)
\(\Rightarrow3^x\left(3+27\right)=810\)
\(\Rightarrow3^x.30=810\)
\(\Rightarrow3^x=27\Rightarrow x=3\)
`[101]`
`3^x . 3 + 3^x . 27 = 810`
`3^x . 30 = 810`
`3^x = 27`
`-> x = 3`.
\(\left(2x+3\right)^2=\frac{9}{121}\\ \left(3x-1\right)^3=-\frac{8}{27}\)
(x-2/9)^3=(2/30)^6
(3x^2-51)^2n=(-24)^2n
(8x-1)^2n+1=5^2n+1
x nhân 5=x 2
(3x -1 )2017=(3x -1 )2018
(x-1) x+ 2=(x-1)x
tính: a)(-1)x(-1)^2x(-1)^3x(-1)^4x...x(-1)^9x(-1)^10
b)[1/100-1^2]x[1/100-(1/2)^2]x[1/100-(1/3)^2]x...x[1/100-(1/20)^2]
Tìm x biết
a)\(\frac{27}{3x}=3\)
b) \(\left(2x-1\right)^3=-125\)
c) \(\left(x-1\right)^{x+2}=x-1^{x+4}\)
2) Tìm x \in∈ N*
a)27<3x<3.81
b)415.915<2x.3x<1816.216
c)(2x-1)6=(2x-1)8
giúp mình nha, mình đang cần gấp
Tìm \(x\), biết :
a) \(\left(2x+3\right)^2=\dfrac{9}{121}\)
b) \(\left(3x-1\right)^3=-\dfrac{8}{27}\)
(2x+1)3 = -8
(3x+2)2 = 16
Mong các bạn giúp.mk đang gấp.
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1/ tìm x,biết:
(4x-3)4=(4x-3)2
2/có hay không số hữu tỉ x thỏa mãn:
(2x+3)2+(3x-2)4=0
\(\dfrac{3x+2}{4}\) =\(\dfrac{2y+2}{5}\)=\(\dfrac{3x+2y+4}{4,5x}\)