\(2x+3=0\Leftrightarrow2x=-3\Leftrightarrow x=-\frac{3}{2}\)
=> 2x = - 3
\(\Rightarrow x=-\frac{3}{2}\)
2x+3=0
2x = 0 - 3
2x = -3
x = -3 : 2
x = -1,5
\(2x+3=0\Leftrightarrow2x=-3\Leftrightarrow x=-\frac{3}{2}\)
=> 2x = - 3
\(\Rightarrow x=-\frac{3}{2}\)
2x+3=0
2x = 0 - 3
2x = -3
x = -3 : 2
x = -1,5
tìm x biết
a, x(2x-7)-4x+14=0
b, x(x-1)+2x-2=0
c, 2x^3+3x^2+2x+3=0
d, x^3+6x^2+11x+6=0
Tìm x,biết :
a) 2x^2-7x+5=0
b) x(2x-5) - 4x+10=0
c) (x-5)(x+5) - x(x-2)=15
d) x^2(2x-3) - 12+8x=0
e) x(x - 1)+5x - 5=0
f) (2x-3)^2 - 4x(x - 1)=5
g) x(5 - 2x)+2x(x - 1)=13
h)2(x+5)(2x - 5)+(x - 1)(5 - 2x)=0
Tim x biết
a)2x(x-5)-x(3+2x)=26
b)5x(x-1)=x-1
C)2(x+5)-x^2-5x=0
d)(2x-3)^2(x+5)=0
e)3x^3-48x=0
f)x^3+x^2-4x=0
1)tim x
a)(x-2)(2x+3)=0 b)x^2-6x+9=0 c)x^2-(x+1)^2=0
d)x(2x-4)-2x(x+3)=20 e)3x(x-4)+12x-48=0 f)4x^2+4x= -1
g)(2x-3)^2+(x-3)(2x+3)=0
Bài 1: CMR các đa thức sau luôn dương vs mọi giá trị biến số:
a) x^2 + x +1
b) x^2 + 3x+3
c) x^2 + y^2 + 2(x-2y) +6
d) 2x^2 + y^2 + 2x( y-1) +2
Bài 2: Phân tích thành nhân tử:
a) x^2 + 2x-3
b) x^2 - 10x +9
c) x^2 - 2x -15
d) x^2 - 2x -48
e) x^2 - 10x+24
f)4x^2 + 4x -15
g) 3x^2 - 7x +2
h) 4x^2 - 5x +1
Bài 3: Tìm x biết :
a) x^2 +5x+6=0
b) x^2 - 10x + 16=0
c) x^2 - 10x +21=0
d) x^2 - 2x -3 =0
e) 2x^2 + 7x +3=0
f) x^2 - x- 6=0
Bài 4:
a)x^3 + 2x^2 - 3=0
b) x^3 - 7x -6=0
c) x^3 + x^2 +4=0
d) x^3 - 2x^2 - x+2 =0
lm giups mk vs ạ,mk cảm ơn rất nhiều
tìm x,biết:
a) x2-2x-3=0
b) 2x2+5x-3=0
Tìm x :
a) 3x( x - 10 ) = x - 10
b) x( x + 7 ) - ( 4x + 28 ) = 0
c) x( x - 4 ) = 2x - 8
d) ( 2x + 3 )( x - 1 ) + ( 2x - 3 )( x - 1 ) = 0
giai PT
a,(y-1)2=9
b,(x-4)2-25=0
c,(x-3)2-(x-1)2=0
d,(3x-7)2-4(x+1)2=0
e,2x(x-5)-x(2x+3)=26
f,5x(x-1)=x-1
g,x3+2x-3=0
h,x3-5x2+8x-4=0
i,x3-7x+6=0
k,x3-9x2+6x+16=0
giai PT
a,(y-1)2=9
b,(x-4)2-25=0
c,(x-3)2-(x-1)2=0
d,(3x-7)2-4(x+1)2=0
e,2x(x-5)-x(2x+3)=26
f,5x(x-1)=x-1
g,x3+2x-3=0
h,x3-5x2+8x-4=0
i,x3-7x+6=0
k,x3-9x2+6x+16=0
giai PT
a,(y-1)2=9
b,(x-4)2-25=0
c,(x-3)2-(x-1)2=0
d,(3x-7)2-4(x+1)2=0
e,2x(x-5)-x(2x+3)=26
f,5x(x-1)=x-1
g,x3+2x-3=0
h,x3-5x2+8x-4=0
i,x3-7x+6=0
k,x3-9x2+6x+16=0