Question

2x+2y+3xy.(x+y)+5.(x^3.y^2+x^2.y^3)+4 biết x+y=0

Answer 1

\(2x+2y+3xy\left(x+y\right)+5\left(x^3y^2+x^2y^3\right)+4=2\left(x+y\right)+3xy\left(x+y\right)+5x^2y^2\left(x+y\right)+4=2.0+3xy.0+5x^2y^2.0+4=4\)

Answer 2

\(2x+2y+3xy\left(x+y\right)+5\left(x^3y^2+x^2y^3\right)+4\)

\(=2\left(x+y\right)+3xy\left(x+y\right)+5\left(xy\right)^2\cdot\left(x+y\right)+4\)

=4