Question

2^x+1 + 2^x+3 = 160

Answer 1

ta có

2^{x+1 ₌} 2¹ . 2^x

2^x+3 = 2³ . 2^x= 8 . 2

Answer 2

thiếu

160=128+32=2⁷ +2⁵

x=4

Answer 3

Ta có: 2^x+1+2^x+3=160

\(\Leftrightarrow2^x.2^1+2^x.2^3=160\)

\(\Leftrightarrow2^x.\left(2^1+2^3\right)=160\)

\(\Leftrightarrow2^x.\left(2+8\right)=160\)

\(\Leftrightarrow2^x.10=160\)

\(\Leftrightarrow2^x=160:10=16\)

\(\Leftrightarrow2^x=2^4\)

Để: 2^x=2⁴ thì: x=4

Vậy: x=4

Answer 4

\(2^{x+1}+2^{x+3}=160\\ \Leftrightarrow\left(1+2^2\right)+2^{x+1}=160\\ \Leftrightarrow5.2^{x+1}=160\\ \Leftrightarrow2^{x+1}=32\\ \Leftrightarrow2^{x+1}=2^5\\ \Leftrightarrow x+1=5\\ \Leftrightarrow x=5-1\\ \Leftrightarrow x=4\)

Vậy $x=4$

Answer 5

\(2^{x+1}+2^{x+3}=160\)

⇔ \(2^x\) (\(2^1+2^3\) ) = 160

⇔ \(2^x\) ( 2 + 8 ) = 160

⇔ \(2^x\). 10 = 160

⇔ \(2^x=160\) :10

⇔ \(2^x\) = 16

⇔ \(2^4=16\)

Vậy x=4

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