\(2\left(x-1\right)+3\left(x-2\right)=x-4\)
\(\Leftrightarrow2\left(x-1\right)+3\left(x-2\right)-x+4=0\)
\(\Leftrightarrow2x-2+3x-6-x+4=0\)
\(\Leftrightarrow4x-4=0\)
\(\Leftrightarrow4x=4\)
\(\Leftrightarrow x=1\)
Vậy ........................
2.(x-1)+3.(x-2)=x-4
\(\Leftrightarrow2x-2+3x-6-x+4=0\)
\(\Leftrightarrow4x=4\)
\(\Leftrightarrow x=1\)