\(\left(2x-1\right)^2=\frac{1}{4}\)
\(\Rightarrow\left(2x-1\right)^2=\left(\frac{1}{2}\right)^2\)
\(\left(2x-1\right)=\frac{1}{2}\)
\(2x=\frac{1}{2}+1\)
\(2x=\frac{3}{2}\)
\(x=\frac{3}{2}\div2\)
\(x=\frac{3}{4}\)
Vậy \(x=\frac{3}{4}\)
(2x-1)^2=1/4
(2x-1)^2=(1/2)^2
2.x-1=1/2
2.x =1,5
x =0,75
\(\left(2x-1\right)^2=\frac{1}{4}\)
\(\Rightarrow\left(2x-1\right)^2=\left(\frac{1}{2}\right)^2\)
\(\Rightarrow2x-1=\frac{1}{2}\)
\(\Rightarrow2x=\frac{1}{2}+1\)
\(\Rightarrow2x=\frac{3}{2}\)
\(\Rightarrow x=\frac{\frac{3}{2}}{2}=\frac{3}{4}\)
Vậy ...
