2014(x - 12) = 0
⇔ x - 12 = 0
⇔ x = 0 + 12
⇔ x = 12
Vậy x = 12
Theo đề ta có:
2014.(x-12)=0
\(\left[{}\begin{matrix}\Rightarrow\left(x-12\right)=\dfrac{0}{2014}\\\Rightarrow\left(x-12\right)=0\\\Rightarrow x=0+12\\\Rightarrow x=12\end{matrix}\right.\)
2014(x-12)=0
x-12 = 0:2014
x-12 = 0
x = 0+12
x = 12
Vậy x=12
2014(x-12)=0
x-12 =0
x =0+12
x =12
Vậy x =12