Bài 1:
a: \(\Leftrightarrow\left\{{}\begin{matrix}x>=1\\2x^2-3x-5=x^2-2x+1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=1\\x^2-x-6=0\end{matrix}\right.\Leftrightarrow x=3\)
b: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(3x-2x+6\right)\left(3x+2x-6\right)=0\end{matrix}\right.\Leftrightarrow x=6\)