\(125+2^3:2^2+\left(5^2+8\right).\)
\(=125-2+\left(25+8\right).\)
\(=123+33=156.\)
Đúng 0
Bình luận (0)
Violympic toán 7
Các câu hỏi tương tự
\(\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^3\cdot3\right)+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\) .Tính tổng
a, \(\frac{-5}{8}-x:3\frac{5}{6}+7\frac{3}{4}=-2\)
b,\(\frac{3}{4}:2\frac{4}{9}-\left|-3x+2\frac{2}{3}\right|=\frac{3}{4}\)
c, \(\left(\frac{4}{5}\right)^{2x+5}=\frac{256}{625}\)
d,\(\left(x-\frac{2}{15}\right)^3=\frac{8}{125}\)
Thực hiện phép tính
a, A = \(\left(\dfrac{1}{4\times9}+\dfrac{1}{9\times14}+\dfrac{1}{14\times19}+....+\dfrac{1}{44\times49}\right)\times\dfrac{1-3-5-7-....-49}{89}\)
b, B = \(\dfrac{2^{12}\times3^5-4^6\times9^2}{\left(2^2\times3\right)^6+8^4\times3^5}-\dfrac{5^{10}\times7^3-25^5\times49^2}{\left(125\times7\right)^3-5^9\times14^3}\)
Rút gọn :
\(A=\dfrac{49^{24}.125^{10}.2^8-5^{10}.7^{49}.2^{10}}{-\left(-5^{29}\right)\left(-16\right)^2.7^{48}}\)
1.Tính :
a) 1253 : 57
b) \(\left(\dfrac{2}{7}\right)^{18}:\left(\dfrac{4}{49}\right)^5:\left(\dfrac{8}{343}\right)^2\)
c) 3 - \(\left(-\dfrac{7}{9}\right)^0+\left(\dfrac{1}{3}\right)^5.3^5\)
d) \(\dfrac{45^{10}.5^{20}}{75^{15}}\)
thực hiên phép tính :
a, left(3^2right)^2-left(2^3right)^2-left(-5^2right)^2
b, 2^3+3.left(-dfrac{1}{2}right)^0-left(dfrac{1}{2}right)^2.4+left(left(-2right)^2:dfrac{1}{2}right):8
c, left(4.2^5right):left(2^3.dfrac{1}{16}right)
d, Adfrac{2^{12}.3^5-4^6.9^2}{left(2^2.3right)^6+8^4.3^5}-dfrac{5^{10}.7^3-25^5.49^2}{left(125.7right)^3+5^9.14^3}
Đọc tiếp
thực hiên phép tính :
a, \(\left(3^2\right)^2-\left(2^3\right)^2-\left(-5^2\right)^2\)
b, \(2^3+3.\left(-\dfrac{1}{2}\right)^0-\left(\dfrac{1}{2}\right)^2.4+\left(\left(-2\right)^2:\dfrac{1}{2}\right):8\)
c, \(\left(4.2^5\right):\left(2^3.\dfrac{1}{16}\right)\)
d, \(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
1. a) Thực hiện phép tính:
\(A=\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
b) Chứng minh rằng với mọi số nguyên dương n thì 3n + 2 - 2n + 2 + 3n - 2n chia hết cho 10.
tính
\(\dfrac{\left(5^4-5^3\right)^3}{125^4}\) ; \(\dfrac{9^3}{\left(3^4-3^3\right)^2}\) ;\(\dfrac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
Tìm x,y biết :
a)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
b)\(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)
c)\(\left(0,4x-1,3\right)^2=5,29\)