\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}\)
\(=1-\dfrac{1}{5}\)
\(=\dfrac{4}{5}\)
\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}\)
\(=1-\dfrac{1}{5}\)
\(=\dfrac{4}{5}\)
Hãy điền các dấu +,-,x,:,( ), ngoặc vuông, ngoặc nhọn,... để kết quả là -1
1...2...3...4=-1
1...2...3...4...5=-1
1...2...3...4...5...6=-1
1...2...3...4...5...6...7=-1
1...2...3...4...5...6...7...8=-1
1...2...3...4...5...6...7...8...9=-1
1...2...3...4...5...6...7...8...9...10=-1
Bài2:Tìm x biết
a.1/3+2/3:x=-7
b.1/3x+2/5(x-1)=0
c.(2x-3)(6-2x)=0
d.x:3/4+1/4=-2/3
e.-2/3-1/3(2x-5)=3/2
f.2 l1/2x-1/3l-3/2=1/4
g.3/4-2.l2x-2/3l=2
h.(-0,6x-1/2).3/4-(-1)=1/3
i.(3x-1)(-1/2x+5)=0
j.1/4+1/3:(2x-1)=-5
k.(2x+3/5)2-9/25=0
l.3(3x-1/2)3+1/9=0
m.-5(x+1/5)-1/2(x-2/3)=3/2x-5/6
n.3(x-1/2)-5(x+3/5)=-x+1/5
1. | 4-2x | . 1/3 = 1/3
2. (-3)² : | x+(-1) | = (-3)
3. | 3/2 -x | + (-4/5) = -14/5
4. (-4/3) - | 2x + (-1) | = -7/3
5. -9 . | 36 - x/2 | = (-54)
6. 0,75 - | (-x) + 1/3 | = 0,25
7. (-6/5) + | x-9 |= (-6/5)
8. (-4) . | 3x - 1/5 | = 12
1. 1+ (-2) + 3+ (-4) + . . . +19 + (-20)
2. 1 - 2 + 3- 4 + . . . + 99 - 100
3. -1 + 3 -5 + 7 - . . . +97 - 99
4. 1+ 2 - 3+ 4 + . . . +97 + 98 - 99 - 100
a) 6/5 . 3/4 - 1/2 : 4/3 - 3/4
b) 4/5.(1/3-1/4-5/6)
3/5- -1/2 -5/7-1/3 -2/5- -3/4 -5-1/6
SGK ?4 (33)
a) -1/2 + 2/3 - 3/4 + 4/5 - 5/6 + 6/7 + 5/6 - 4/5 + 3/4 - 2/3 + 1/2
giúp em với ạ
\(\dfrac{1}{2}×\dfrac{1}{2}+\dfrac{1}{2}×\dfrac{1}{3}+\dfrac{1}{3}×\dfrac{1}{4}+\dfrac{1}{4}×\dfrac{1}{5}+\dfrac{1}{5}×\dfrac{1}{6}\)
Tính giá trị biểu thức :
\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{4}+\dfrac{2}{4}+\dfrac{3}{4}\right)-\left(\dfrac{1}{5}+\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{4}{5}\right)+\left(\dfrac{1}{6}+\dfrac{2}{6}+\dfrac{3}{6}+\dfrac{4}{6}+\dfrac{5}{6}\right)-\left(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\right)+...+\left(100+...+\dfrac{99}{100}\right)\)