a) 3| 2x + 5| -4= 1
=>3|2x+5|=5
\(\Rightarrow\left|2x+5\right|=\frac{5}{3}\)
\(\Rightarrow2x+5=-\frac{5}{3}\) hoặc \(\frac{5}{3}\)
Xét \(2x+5=-\frac{5}{3}\)
\(\Rightarrow2x=\frac{20}{3}\Leftrightarrow x=-\frac{10}{3}\)
Xét \(2x+5=\frac{5}{3}\)
\(\Rightarrow2x=-\frac{10}{3}\)
\(\Rightarrow x=-\frac{5}{3}\)
b) 7- 2|1 -3x|= -5
=>2|1-3x|=12
=>|1-3x|=6
=>1-3x=6 hoặc -6
Xét 1-3x=6
=>3x=7 <=>\(x=\frac{7}{3}\)
Xét 1-3x=-6
=>3x=-5 <=>\(x=-\frac{5}{3}\)