Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
Rút gọn biểu thức:
1) sqrt{left(1-sqrt{2}right)^2}+sqrt{left(sqrt{2}+3right)^2}
2) sqrt{left(sqrt{3}-2right)^2}+sqrt{left(sqrt{3}-1right)^2}
3) left(sqrt{19}-3right)left(sqrt{19}+3right)
4) 4x+sqrt{left(x-12right)^2}left(xge2right)
5) frac{sqrt{7}+sqrt{5}}{sqrt{7}-sqrt{5}}+frac{sqrt{7}-sqrt{5}}{sqrt{7}+sqrt{5}}
6) x+2y-sqrt{left(x^2-4xy+4y^2right)^2}left(xge2yright)
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Rút gọn biểu thức:
1) \(\sqrt{\left(1-\sqrt{2}\right)^2}+\sqrt{\left(\sqrt{2}+3\right)^2}\)
2) \(\sqrt{\left(\sqrt{3}-2\right)^2}+\sqrt{\left(\sqrt{3}-1\right)^2}\)
3) \(\left(\sqrt{19}-3\right)\left(\sqrt{19}+3\right)\)
4) \(4x+\sqrt{\left(x-12\right)^2}\left(x\ge2\right)\)
5) \(\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}-\sqrt{5}}+\frac{\sqrt{7}-\sqrt{5}}{\sqrt{7}+\sqrt{5}}\)
6) \(x+2y-\sqrt{\left(x^2-4xy+4y^2\right)^2}\left(x\ge2y\right)\)
14 tháng 7 2019 lúc 20:50
1)sqrt{x+2}-sqrt{3-x}x^2-6x+9
2)sqrt{x}-sqrt{x-1}sqrt{x+8}-sqrt{x+3}
3)left(sqrt{1+x}-1right)left(sqrt{1-x}+1right)2x
4)sqrt[3]{x+1}+sqrt[3]{x-1}4x+1
5/left(x-3right)left(x+1right)-4left(x-3right)left(sqrt{frac{x+1}{x-3}}right)-3
6)sqrt{x^2-2x}+sqrt{x^2-7x}sqrt{x^2-23x}
làm nhanh giúp mk nhoa mk mai mk nộp rồi :(( cảm ơn ạ
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1)\(\sqrt{x+2}-\sqrt{3-x}=x^2-6x+9\)
2)\(\sqrt{x}-\sqrt{x-1}=\sqrt{x+8}-\sqrt{x+3}\)
3)\(\left(\sqrt{1+x}-1\right)\left(\sqrt{1-x}+1\right)=2x\)
4)\(\sqrt[3]{x+1}+\sqrt[3]{x-1}=4x+1\)
5/\(\left(x-3\right)\left(x+1\right)-4\left(x-3\right)\left(\sqrt{\frac{x+1}{x-3}}\right)=-3\)
6)\(\sqrt{x^2-2x}+\sqrt{x^2-7x}=\sqrt{x^2-23x}\)
làm nhanh giúp mk nhoa mk mai mk nộp rồi :(( cảm ơn ạ
giải hệ:
a) left{{}begin{matrix}sqrt{x+3y}+sqrt{x+y}2sqrt{x+y}+y-x1end{matrix}right.
b) left{{}begin{matrix}x+y+frac{1}{x}+frac{1}{y}4x^2+y^2+frac{1}{x^2}+frac{1}{y^2}4end{matrix}right.
c) left{{}begin{matrix}left(x-frac{1}{y}right)left(y+frac{1}{x}right)22x^2y+xy^2-4xy2x-yend{matrix}right.
d) left{{}begin{matrix}2x^2+xyy^2-3y+2x^2-y^23end{matrix}right.
e) left{{}begin{matrix}x^2+y^2+z^2+2xy-xz-zy3x^2+y^2-2xy-xz+zy-1end{matrix}right.
f) left{{}begin{matrix}x^2-y^2+5x-y+60x^2+left(x-yright)...
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giải hệ:
a) \(\left\{{}\begin{matrix}\sqrt{x+3y}+\sqrt{x+y}=2\\\sqrt{x+y}+y-x=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}x+y+\frac{1}{x}+\frac{1}{y}=4\\x^2+y^2+\frac{1}{x^2}+\frac{1}{y^2}=4\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}\left(x-\frac{1}{y}\right)\left(y+\frac{1}{x}\right)=2\\2x^2y+xy^2-4xy=2x-y\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}2x^2+xy=y^2-3y+2\\x^2-y^2=3\end{matrix}\right.\)
e) \(\left\{{}\begin{matrix}x^2+y^2+z^2+2xy-xz-zy=3\\x^2+y^2-2xy-xz+zy=-1\end{matrix}\right.\)
f) \(\left\{{}\begin{matrix}x^2-y^2+5x-y+6=0\\x^2+\left(x-y\right)^2=2+\sqrt{6x+7}+2\sqrt{x+y+1}\end{matrix}\right.\)
1) \(\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}-\sqrt{5}}+\frac{\sqrt{7}-\sqrt{5}}{\sqrt{7}+\sqrt{5}}\)
2) \(x+2y-\sqrt{\left(x^2-4xy+4y^2\right)^2\left(x\ge2y\right)}\)
3) 4x + \(\sqrt{\left(x-12\right)^2}\left(x\ge2\right)\)
Rút gọn biểu thức:
1) Pfrac{x^2-sqrt{x}}{x+sqrt{x}+1}-frac{2x+sqrt{x}}{sqrt{x}}+frac{2cdotleft(x-1right)}{sqrt{x}-1}
2) Pleft(frac{sqrt{x}-2}{sqrt{x}-1}-frac{sqrt{x}+2}{x+2sqrt{x}+1}right)cdotfrac{left(1-xright)^2}{2}
3) Bleft(frac{1-asqrt{a}}{1-sqrt{a}}+sqrt{a}right)cdotleft(frac{1+asqrt{a}}{1+sqrt{a}}-sqrt{a}right)
4) Kleft(frac{sqrt{a}}{sqrt{a}-1}-frac{1}{a-sqrt{a}}right)divleft(frac{1}{sqrt{a}+1}-frac{2}{a-1}right)
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Rút gọn biểu thức:
1) \(P=\frac{x^2-\sqrt{x}}{x+\sqrt{x}+1}-\frac{2x+\sqrt{x}}{\sqrt{x}}+\frac{2\cdot\left(x-1\right)}{\sqrt{x}-1}\)
2) \(P=\left(\frac{\sqrt{x}-2}{\sqrt{x}-1}-\frac{\sqrt{x}+2}{x+2\sqrt{x}+1}\right)\cdot\frac{\left(1-x\right)^2}{2}\)
3) \(B=\left(\frac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\cdot\left(\frac{1+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a}\right)\)
4) \(K=\left(\frac{\sqrt{a}}{\sqrt{a}-1}-\frac{1}{a-\sqrt{a}}\right)\div\left(\frac{1}{\sqrt{a}+1}-\frac{2}{a-1}\right)\)
Cho x, y thỏa mãn điều kiện:\(\left(y+\sqrt{1+y^2}\right)\left(x+\sqrt{1+x^2}\right)+1.\)Tính giá trị của biểu thức x7+y7+2x5+2y5-3x3-3y3+4x+4y+100
1/Rút gọn
Afrac{left(sqrt{x}+1right)left(x-sqrt{xy}right)left(sqrt{x}+sqrt{y}right)}{left(x-yright)left(sqrt{x^3+x}right)}(x0; y0; x#y)
B left(frac{1}{sqrt{x}+1}-frac{1}{x+sqrt{x}}right):frac{x-sqrt{x}+1}{xsqrt{x}+1}( x0)
Cleft(frac{x+1}{sqrt{x}}+2right).frac{sqrt{x}}{left(sqrt{x}+1right)left(xsqrt{x}+1right)}(x0)
Dleft(frac{xsqrt{x}-1}{sqrt{x}-1}+sqrt{x}right):left(x-1right)-frac{2}{sqrt{x}-1}(x0; x#1)
giúp em với ạ em đang cần gấp ạ
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1/Rút gọn
A=\(\frac{\left(\sqrt{x}+1\right)\left(x-\sqrt{xy}\right)\left(\sqrt{x}+\sqrt{y}\right)}{\left(x-y\right)\left(\sqrt{x^3+x}\right)}\)(x>0; y>0; x#y)
B= \(\left(\frac{1}{\sqrt{x}+1}-\frac{1}{x+\sqrt{x}}\right):\frac{x-\sqrt{x}+1}{x\sqrt{x}+1}\)( x>0)
C=\(\left(\frac{x+1}{\sqrt{x}}+2\right).\frac{\sqrt{x}}{\left(\sqrt{x}+1\right)\left(x\sqrt{x}+1\right)}\)(x>0)
D=\(\left(\frac{x\sqrt{x}-1}{\sqrt{x}-1}+\sqrt{x}\right):\left(x-1\right)-\frac{2}{\sqrt{x}-1}\)(x>=0; x#1)
giúp em với ạ em đang cần gấp ạ
Tìm x
a)\(\sqrt{x-1}=2\left(x\ge1\right)\)
b)\(\sqrt{3-x}=4\left(x\le3\right)\)
c)\(2.\sqrt{3-2x}=\dfrac{1}{2}\left(x\le\dfrac{3}{2}\right)\)
d)\(4-\sqrt{x-1}=\dfrac{1}{2}\left(x\ge1\right)\)
e)\(\sqrt{x-1}-3=1\)
f)\(\dfrac{1}{2}-2.\sqrt{x+2}=\dfrac{1}{4}\)
Giải phương trình:
a) sqrt{x+2+3sqrt{2x-5}}+sqrt{x-2-sqrt{2x-5}}2sqrt{2}
b) sqrt{x+1}+2left(x+1right)x-1+sqrt{1-x}+3sqrt{1-x^2}
c) left(sqrt{1+x}-1right)left(sqrt{1-x}+1right)2x
d) 2left(x^2+2x+3right)5sqrt{left(x+1right)^3}
(Các bạn giúp mình sớm nhé! Thank!)
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Giải phương trình:
a) \(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
b) \(\sqrt{x+1}+2\left(x+1\right)=x-1+\sqrt{1-x}+3\sqrt{1-x^2}\)
c) \(\left(\sqrt{1+x}-1\right)\left(\sqrt{1-x}+1\right)=2x\)
d) \(2\left(x^2+2x+3\right)=5\sqrt{\left(x+1\right)^3}\)
(Các bạn giúp mình sớm nhé! Thank!)