a, Ta có:
\(\sqrt{2}>\sqrt{1}\Rightarrow\sqrt{2}>1\)
\(\Rightarrow-3+\sqrt{2}>-3+\sqrt{1}\)
\(\Rightarrow-3+\sqrt{2}>-3+1\)
\(\Rightarrow-3+\sqrt{2}>-2\)
Chúc bạn học tốt!!!
\(\sqrt{5}>\sqrt{4}=2\)
\(\sqrt{57}>\sqrt{49}=7\)
\(\Rightarrow\sqrt{5}+\sqrt{57}>2+7\)
Vậy \(\sqrt{5}+\sqrt{57}>9\)
b)\(\sqrt{5}+\sqrt{57}\ge\sqrt{5}+\sqrt{49}=\sqrt{5}+7\)
mà \(\sqrt{5}\ge\sqrt{4}\Rightarrow\sqrt{5}+7\ge\sqrt{4}+7=9\)
=> \(\sqrt{5}+\sqrt{57}\ge9\)